3x^2-2x+0.25=0

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Solution for 3x^2-2x+0.25=0 equation: 



3x^2-2x+0.25=0

a = 3; b = -2; c = +0.25;
Δ = b2-4ac
Δ = -22-4·3·0.25
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-1}{2*3}=\frac{1}{6}
=1/6
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+1}{2*3}=\frac{3}{6}
=1/2
$

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